$\displaystyle \int_c\frac{{e}^{z } }{ ({{z}^{2 }-9 })^{2 } } dz $where c is the positively oriented circle $\displaystyle |z+2|=2$ So the formula is $\displaystyle \frac{2\pi i {f}^{(n-1) } (z)}{(n-1)! } $ $\displaystyle f(z) = {e}^{ z} and n = 2$ So my answer is $\displaystyle 2\pi i {e}^{-3 } $ But according to my teacher it is over 27