where c is the positively oriented circle So the formula is So my answer is But according to my teacher it is over 27 (Headbang)

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- May 12th 2011, 11:24 AMadam_leedsContour Integration
where c is the positively oriented circle So the formula is So my answer is But according to my teacher it is over 27 (Headbang)

- May 12th 2011, 11:29 AMAmer
f(z) is not e^z in this question

\frac{e^z}{(z^2-3)^(z^2+3)^2 } = \frac{\frac{e^z}{(z+3)^2}}{(z-3)^2} - May 12th 2011, 11:35 AMadam_leeds
- May 12th 2011, 11:39 AMadam_leeds
- May 12th 2011, 12:31 PMMondreus

As you can see, only one of the poles (z=-3) lies within the given circle, so we let and use Cauchy's integral formula for f(-3):

- May 12th 2011, 12:32 PMAmer
http://latex.codecogs.com/png.latex?...z-3)^2(z+3)^2}

we have two singular points -3,3 but 3 is outside the circle

but -3 is inside so the singular point for the function is -3

http://latex.codecogs.com/png.latex?...)^2}}{(z+3)^2} the function is

http://latex.codecogs.com/png.latex?...f(z)}{(z+3)^2}