Hey all some help with the following proof would be appreciated: Let L = limit from k to infinity of x-sub-k If x-sub-k from k=0 to infinity is decreasing, then x-sub-k >= L for all k >= 0 Thanks a bunch!
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If $\displaystyle x_{k_0}<L$ for some $\displaystyle k_0$ , choose $\displaystyle \epsilon=(L-x_{k_0})/2$ and you'll get a contradiction.
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