1. ## Fibonacci Power Series

I am having trouble with this question:
Define $F(x)=\displaystyle\sum\limits_{n=0}^\infty F_nx^n$ where $F_n$ is the nth Fibonacci number. Determine the radius of convergence of F(x). Using $F_{n+2} = F_{n+1} + F_n$ find F(x) in closed form.

I think I have managed to do the radius of convergence but I don't know if I am correct. Is the answer the solution to $x^2-x-1$ i.e. $\frac{2}{1+\sqrt{5}}$?

As for the second part I have completely no idea and would appreciate some help starting the question (I should note I have tried writing F(x) out in terms of the formula but have not gotten anywhere with this)

2. Originally Posted by worc3247
I am having trouble with this question:
Define $F(x)=\displaystyle\sum\limits_{n=0}^\infty F_nx^n$ where $F_n$ is the nth Fibonacci number. Determine the radius of convergence of F(x). Using $F_{n+2} = F_{n+1} + F_n$ find F(x) in closed form.

I think I have managed to do the radius of convergence but I don't know if I am correct. Is the answer the solution to $x^2-x-1$ i.e. $\frac{2}{1+\sqrt{5}}$?

As for the second part I have completely no idea and would appreciate some help starting the question (I should note I have tried writing F(x) out in terms of the formula but have not gotten anywhere with this)
The explicit form for the Fibonacci's number is...

$\displaystyle F_{n}= \frac{\varphi^{n} - (-1)^{n}\ \varphi^{-n}}{\sqrt{5}}$ (1)

... where...

$\displaystyle \varphi= \frac{1+\sqrt{5}}{2}$ (2)

... so that is...

$\displaystyle F(x)= \sum_{n=0}^{\infty} F_{n}\ x^{n} = \frac{1}{\sqrt{5}}\ \{\sum_{n=0}^{\infty} (\varphi\ x)^{n} - \sum_{n=0}^{\infty} (-\frac{x}{\varphi})^{n}\}$ (3)

Now (3) is the sum of two series... the first converges for $|x|<\varphi^{-1}$ , the second for $|x|<\varphi$ and is $\varphi^{-1}< \varphi$ so that...

Kind regards

$\chi$ $\sigma$

3. Do you then just take geometric series and get:
$F(x)=\frac{1}{\sqrt{5}}(\frac{1}{1-\varphi x} - \frac{\varphi}{\varphi + x})$?
Cheers

4. Originally Posted by worc3247
Do you then just take geometric series and get:
$F(x)=\frac{1}{\sqrt{5}}(\frac{1}{1-\varphi x} - \frac{\varphi}{\varphi + x})$?
Cheers
Yes!... it does!...

Kind regards

$\chi$ $\sigma$