# Harmonic Functions

• Mar 6th 2011, 05:28 PM
mulaosmanovicben
Harmonic Functions
Show by example that a harmonic function need not have an analytic completion in a multiply connected domain. [HINT: Consider ln(|z|), z a complex number]

well I considered u=ln(x^2+y^2) where z=x+iy

and I figured out it was harmonic (second partial derivitives are 0) but I do not know where to go from there.
• Mar 6th 2011, 07:03 PM
xxp9
what is the definition of analytic completion?
• Mar 7th 2011, 01:39 PM
mulaosmanovicben
Quote:

Originally Posted by xxp9
what is the definition of analytic completion?

Analytic completion for a function u is when there exists a harmonic function v in a simply connected domain such that u+iv is analytic.
• Mar 7th 2011, 07:01 PM
xxp9
So let u=ln|z|, u is hormonic in the domain of punctured plane $R^2 - {0}$.
Since an analytic function is determined in any open sub-set of the plane the analytic completion is unique( up to a constant), if it exists.
So the only possible analytic completion for u would be f=lnz=u + i argz
While f can only be defined on a plane where a half line is cut.