Thread: self-adjoint linear operator

If T:V->V is a self-adjoint linear transformation, V is a finite-dimensional inner product space over C, how can I prove that T has n distinct eigenvalues?

Originally Posted by guin

If T:V->V is a self-adjoint linear transformation, V is a finite-dimensional inner product space over C, how can I prove that T has n distinct eigenvalues?

That is false, choose for example (the identity map) and .


Fernando Revilla