Hello

I'm having difficulty with part (ii) of the first link.

I used the result from part (i) and was able to get g(Tb)-g(Ta)- integral from Ta to Tb of g(x)/x dx...

I noticed that the g(Ta)-g(Tb) terms cancel and i'm only left with the integral term.

I used by parts on the integral term with u=g(x) , du= g'(x) dv= 1/xdx, v= lnx.

I obtained $\displaystyle \displaystyle = Bln(b/a)- \int_{Ta}^{Tb} lnx(g'(x))dx$

My problem is that I can't seem to get rid of the final integral term. Any help would greatly be appreciated.

I'm also stuck with the question in the second image, I believe that this questions requires me to apply my result from part(ii)?

Thank you.

Question part(ii) ImageShack® - Online Photo and Video Hosting

ImageShack® - Online Photo and Video Hosting