Non dyadic Values
Let 0 < x < 2 be a non-dyadic value expressed as x =summation(d_n/2^n)
; dn = 0 or 1 for all n.
Show that for gm defined as gm=summation(1/2^nh(2^nx) from 0 to m one has
g'm(x) = (-1)^d0 + (-1)^d1 + .... + (-1)^dm
I started looking at some example. First, I had dn=0 if n was odd and 1 if n was even.
Alternatively dn=0 if n is even and 1 if n is odd.
I'm sorry, there is way to little info here to see what's going on. Also, you might want to tex this, it's hard to read.
Originally Posted by kathrynmath