I'm not very clear on what you are asking. Are you trying to show
using the definition?
abs[sin(n)/n] <epsilon
How do I solve for n so that I can find a delta to use in my proof that the limit of sin(n)/n is 0?
Can I just say that since sin has max and min values between 1 and -1 that 1/n < epsilon? and then use 1/epsilon as my delta?