Analytic + bounded --> Uniformly continoius

**skyking** · February 5th 2011, 02:43 PM

Here is a problem I got stuck on.

Let $f$ be analytic and bounded in the half plane $\{z:Rez>0\}$ . Show that for every $c>0$ , $f$ is uniformly continous in the half plane $\{ z:Rez>c\}$ .

I tried the following but got stuck.

for every $\epsilon >0$ choose $\delta = min(\frac{\epsilon}{M},c)$ , where $M$ is the bound of $f$ . So for every $|z_2-z_1|<\delta$ we get by Cauchys Integral formula $|f(z_2)-f(z_1)|=\frac{1}{2\pi}|\int_{C_{\delta}} \frac{f(w)}{w-z_2} - \frac{f(w)}{w-z_1} dw|=\frac{1}{2\pi}|\int_{C_{\delta}} f(w)\frac{z_2-z_1}{(w-z_2)(w-z_1)} dw|\leq \frac{4*2\pi \delta}{2\pi \delta^2}M|z_1-z_2|\leq 2M$ . Which gets me nowhere.

I'd appreciate some direction.