Prove the following using partial sums: 1/(1(1+1)) + 1/(2(2+1)) + 1/(3(3+1)) + ... + 1/(k(k+1)) = 1 as k approaches infinity.
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Originally Posted by thamathkid1729 Prove the following using partial sums: 1/(1(1+1)) + 1/(2(2+1)) + 1/(3(3+1)) + ... + 1/(k(k+1)) = 1 as k approaches infinity. $\displaystyle \displaystyle \frac{1}{k(k+1)}=\frac{1}{k}-\frac{1}{k+1}.$
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