# Math Help - pseudo-sine function?

1. ## pseudo-sine function?

My professor has this exercise in his notes. I may be able to prove it but I don't know what he pseudo-sine function is.
He states:
Let $\sigma$ be the pseudo-sine function. Let $f(x)=x\sigma (1/x)$ for $x\not= 0$. Prove $f$ has a removable discontinuity at $0$.

2. The pseudo-sine function might be $\sigma(x) = \sin(\frac{1}{x})$, for $x\neq 0$.

In this case, we have $f(x) = x\sin(x)$ for $x\neq 0$, and it is not hard to check that this function has a removable discontinuity at $x=0$.

Do you know how to prove this?

Also, you better ask your professor, if this is the right definition of the pseudo-sine function (I recall having seen that name somewhere, definitely involving the function $\sin(\frac{1}{x})$, but it might have been $x\sin(\frac{1}{x})$ or something similar).

3. A more general concept of "pseudo-sine" is any function that is (quas-) periodic and bounded. Of course, for this proof, you only need "bounded". If $a\le \sigma(x)\le b$ then $ax\le x\sigma(x)\le bx$. Then, as x goes to 0, $0\le \lim_{x\to 0} x \sigma(x)\le 0$ so the limit exists and is 0. You only need "exists" to prove there is a removable discontinuity at x= 0.