My professor has this exercise in his notes. I may be able to prove it but I don't know what he pseudo-sine function is.

He states:

Let be the pseudo-sine function. Let for . Prove has a removable discontinuity at .

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- October 25th 2010, 07:16 AMzebra2147pseudo-sine function?
My professor has this exercise in his notes. I may be able to prove it but I don't know what he pseudo-sine function is.

He states:

Let be the pseudo-sine function. Let for . Prove has a removable discontinuity at . - October 25th 2010, 09:05 AMHappyJoe
The pseudo-sine function might be , for .

In this case, we have for , and it is not hard to check that this function has a removable discontinuity at .

Do you know how to prove this?

Also, you better ask your professor, if this is the right definition of the pseudo-sine function (I recall having seen that name somewhere, definitely involving the function , but it might have been or something similar). - October 25th 2010, 04:58 PMHallsofIvy
A more general concept of "pseudo-sine" is any function that is (quas-) periodic and bounded. Of course, for this proof, you only need "bounded". If then . Then, as x goes to 0, so the limit exists and is 0. You only need "exists" to prove there is a removable discontinuity at x= 0.