The back of my textbook says:

1-n*ln((2n+1)/(2n-1)) = O(1/n^2)

Maple verified that:

[1-n*ln((2n+1)/(2n-1))]/[-1/(12x^2)]->1 as n->infinity.

But all my calculations show it to be order 1/n. What am I missing?

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- Oct 24th 2010, 06:19 PM #1

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