Cubic Spline URGENT help!

Here is my question: In order to evaluate http://webwork.sdsu.edu/webwork2_fil...a95bf8f6f1.png for http://webwork.sdsu.edu/webwork2_fil...e7f1b23391.png, you need
http://webwork.sdsu.edu/webwork2_fil...2326df8651.png

I wrote a program to create a table of the coefficients however im lost on how to find the coef.

Here is my table:
Coefficients [x a b c d]
0.9000 1.3000 0.5396 0 -0.2476
1.3000 1.5000 0.4208 -0.2972 0.9469
1.9000 1.8500 1.0868 1.4073 -2.9564
2.1000 2.1000 1.2949 -0.3666 -0.4466
2.6000 2.6000 0.5934 -1.0365 0.4451
3.0000 2.7000 -0.0222 -0.5025 0.1742
3.9000 2.4000 -0.5034 -0.0322 0.0781
4.4000 2.1500 -0.4771 0.0849 1.3142
4.7000 2.0500 -0.0713 1.2676 -1.5812
5.0000 2.1000 0.2623 -0.1555 0.0431
6.0000 2.2500 0.0808 -0.0261 -0.0047
7.0000 2.3000 0.0146 -0.0401 -0.0244
8.0000 2.2500 -0.1390 -0.1135 0.0175
9.2000 1.9500 -0.3358 -0.0506 -0.0127
10.5000 1.4000 -0.5318 -0.1002 -0.0203
11.3000 0.9000 -0.7312 -0.1490 1.2134
11.6000 0.7000 -0.4929 0.9431 -0.8393
12.0000 0.6000 -0.1413 -0.0640 0.0364
12.6000 0.5000 -0.1789 0.0014 -0.4480
13.0000 0.4000 -0.3928 -0.5361 0.5957
13.3000 0.2500 0 0 0

Attachment 19462

Ok i figured it out. Its actually pretty simple. so lets say you want to solve S(x) when x=11.8
what you do is u go to the table and look for where 11.8 is in between two values.
x a b c d
11.6000 0.7000 -0.4929 0.9431 -0.8393
12.0000 0.6000 -0.1413 -0.0640 0.0364

as you can see 11.8 fits between these two rows SOOO you take the values of the smaller row.
11.6000 0.7000 -0.4929 0.9431 -0.8393

and create the following equation for S(x)


then plug in the value u are solving for x=11.8