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Thread: Epsilion

  1. #1
    Super Member
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    Epsilion

    When trying to prove thar the limit of a seq is unique, i saw in my notes tt for episilion >0, la-bl>2episilion assuming that a and b r the limits of the seq.

    Then from here, why does it mean that la-bl =0?
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  2. #2
    Senior Member Tinyboss's Avatar
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    If you mean $\displaystyle |a-b|<2\varepsilon$ then we get equality because $\displaystyle \varepsilon$ can be arbitrarily small. If a and be were not equal you could choose $\displaystyle \varepsilon$ small enough to break the inequality. Note that any constant multiple of $\displaystyle \varepsilon$ would work just as well.
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