If I start with the triangle inequality: and then I switch the sign on the LHS, which is true: or
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I suppose obviously the second one... So how would I prove: for all ?
Start with: x-z=t y-z=s x-y=t-s
Originally Posted by MichaelMath If I start with the triangle inequality: Start with implies Likewise So . That implies
Thanks mate, I figured it out using Zarathustra's suggestion. Can you get me started on this one?
Start by showing . Note that and add those to together.
Last edited by Plato; October 20th 2010 at 01:26 PM.
I need to read a bit about manipulating inequalities and absolute values... any suggestions?
Originally Posted by MichaelMath I need to read a bit about manipulating inequalities and absolute values... any suggestions? Can you get Do you understand that if then
Okay... So: and the second one...
ok, i got it.
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