# limit superior inequality

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• October 5th 2010, 11:26 AM
ashamrock415
limit superior inequality
Let an, bn be two bounded sequences. Show that

limn-->∞ sup (an+bn) ≤ limn-->∞ sup an + limn-->∞ sup bn
• October 5th 2010, 11:47 AM
emakarov
That's because $\sup_{m\ge n}(a_m+b_m)\le(\sup_{m\ge n}a_m)+(\sup_{m\ge n}b_m)$. Indeed, on the right you can, roughly speaking, choose the largest elements of the sequences $\{a_m\}$ and $\{b_m\}$ independently and then add them, whereas on the left you have to add elements with the same index and then choose the largest.