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Thread: metric space triangle inequality

  1. #1
    Junior Member
    Jan 2010

    metric space triangle inequality

    Let (M,d) be a metric space. Define a new metric as $\displaystyle p(x,y)=\frac{d(x,y)}{1+d(x,y)}$ and prove that $\displaystyle p(x,z)\leq p(x,y)+p(y,z)$

    **Sorry just had a huge breakthrough, this is now solved**
    Last edited by emathinstruction; Sep 28th 2010 at 07:51 PM. Reason: solved
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