Is this correct?

Printable View

- September 24th 2010, 03:10 PMdwsmitharg(\frac{1}{z})

Is this correct? - September 24th 2010, 03:14 PMmr fantastic
- September 24th 2010, 03:17 PMdwsmith
So the the argument of 1 over z is just going to be ?

- September 24th 2010, 03:29 PMPlato
Let’s consider the principal argument, .

The is simply its reflection in the real axis.

You may want to reconsider? - September 24th 2010, 03:34 PMdwsmith
If we pick up from where Mr F stopped, we have the angle as .

Now, my question is then why isn't the - September 24th 2010, 04:06 PMchiph588@
- September 24th 2010, 04:09 PMdwsmith
, yes?

- September 24th 2010, 04:17 PMchiph588@
- September 24th 2010, 04:18 PMzzzoak
I think that