Is this correct?

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- Sep 24th 2010, 03:10 PMdwsmitharg(\frac{1}{z})

Is this correct? - Sep 24th 2010, 03:14 PMmr fantastic
- Sep 24th 2010, 03:17 PMdwsmith
So the the argument of 1 over z is just going to be ?

- Sep 24th 2010, 03:29 PMPlato
Let’s consider the principal argument, .

The is simply its reflection in the real axis.

You may want to reconsider? - Sep 24th 2010, 03:34 PMdwsmith
If we pick up from where Mr F stopped, we have the angle as .

Now, my question is then why isn't the - Sep 24th 2010, 04:06 PMchiph588@
- Sep 24th 2010, 04:09 PMdwsmith
, yes?

- Sep 24th 2010, 04:17 PMchiph588@
- Sep 24th 2010, 04:18 PMzzzoak
I think that