Is this correct?

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- September 24th 2010, 04:10 PMdwsmitharg(\frac{1}{z})

Is this correct? - September 24th 2010, 04:14 PMmr fantastic
- September 24th 2010, 04:17 PMdwsmith
So the the argument of 1 over z is just going to be ?

- September 24th 2010, 04:29 PMPlato
Let’s consider the principal argument, .

The is simply its reflection in the real axis.

You may want to reconsider? - September 24th 2010, 04:34 PMdwsmith
If we pick up from where Mr F stopped, we have the angle as .

Now, my question is then why isn't the - September 24th 2010, 05:06 PMchiph588@
- September 24th 2010, 05:09 PMdwsmith
, yes?

- September 24th 2010, 05:17 PMchiph588@
- September 24th 2010, 05:18 PMzzzoak
I think that