Prove that the sequence sum(i=1 --> n) 1/(10^i) converges.
I'm pretty sure it converges to 1/9 but how to we get there by fixing epsilon?
I'm not sure what you mean by "epsilon convergence" but this is a geometric series.
You should know that for a finite geometric series
$\displaystyle S_n = \frac{a(1 - r^n)}{1 - r}$.
Therefore it is convergent.
You should also be able to see that if you make $\displaystyle n \to \infinity$, i.e. make this an infinite series, since $\displaystyle |r| < 1$, that means $\displaystyle r^n \to 0$ and thus the sum goes to $\displaystyle S_{\infty} = \frac{a}{1 - r}$, which is also convergent.
1) You can simply write | | instead of absval, even with LaTeX.
2) As Prove It said,
$\displaystyle \displaystyle \lim_{n \to \infty} \sum_{i=1}^n \frac{1}{10^i} = \lim_{n \to \infty} \frac{1}{10} \cdot \frac{1 - 10^{-n}}{1 - 10^{-1}}$
Double click on the latex to see the correct code.