Let f:A->B. Let![]()
A and
![]()
B. Show that f preserves inclusion and unions only:
question: f(![]()
![]()
) =f(
)
f(
).
I'm not very good with the latex code and I just want to mention that I'm not sure why some things besides the 0 and the 1 look like subscripts. hopefully its not too confusing.


LinkBack URL
About LinkBacks

