1. ## Metric spaces

Let

$X:=\{{(a_n)^\infty_{n=0} : \sum^{\infty}_{n=0}|a_n|<\infty}\}$

be the space of absolutely covergent sequences.

Define the $l^1$ and $l^{\infty}$ metric on this space by

$d_{l^1}((a_n)^\infty_{n=0}, (b_n)^\infty_{n=0}):=\sum^{\infty}_{n=0}|a_n-b_n|$

$d_{l^\infty}((a_n)^\infty_{n=0}, (b_n)^\infty_{n=0}) := sup_{n\in\mathbb{N}}|a_n-b_n|$

First, I want to show that there exist sequences $x^{(1)}, x^{(2)}, ...$ of elements of $X$ which are convergent with respect to the $d_{l^{\infty}}$ metric but not with respect to the $d_{l^1}$ metric.

Second, that any sequence which converges in the $d_{l^1}$ metric, automatically converges in the $d_{l^{\infty}}$ metric.

Thanks

2. A series that converges in the sup-metric, but not in the 1-metric is for example this:
x_0=(1,0,0,...)
x_1=(1/2,1/2,0,0,...)
x_2=(1/3,1/3,1/3,0,0,...)
x_3=(1/4,1/4,1/4,1/4,0,0,...)
...
x_n=(1/n,1/n,...,1/n,0,0,...) (n times 1/n)
...