I have this function here.

Attachment 18564

Can someone please explain why from 4 < x < 10 it is 7 - x?

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- Aug 14th 2010, 05:31 AMrossy54newbie needing analytical description of a periodic function
I have this function here.

Attachment 18564

Can someone please explain why from 4 < x < 10 it is 7 - x? - Aug 14th 2010, 06:41 AMchiph588@
Well, two points make a line. Take the two endpoints and see what you get.

- Aug 14th 2010, 06:58 AMrossy54
not really sure. From 0 < x < 4 its 3x/4 but cant see why its 7 - x.

- Aug 14th 2010, 07:39 AMchisigma
You have a function...

$\displaystyle f(x)= a_{0} + a_{1}\ x$ (1)

... and is $\displaystyle f(4)=3$ and $\displaystyle f(10)=-3$... then You can find $\displaystyle a_{0}$ and $\displaystyle a_{1}$ in 'standard way'...

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$ - Aug 14th 2010, 02:53 PMVlasev
rossy54, the function changes from place to place. From 0 to 4 it is indeed 3x/4. However, it immediately changes to 7-x when x is between 4 and 10. After that it is a constant.

- Aug 14th 2010, 03:04 PMyeKciM
to make equation of line through two points :

$\displaystyle (y-y_1)=\displasyle \frac{y_2-y_1}{x_2-x_1} \cdot (x-x_1) $

now your two points $\displaystyle M_1 (4,3) \; M_2(10,-3) $

so you will have :D

$\displaystyle \displaystyle (y-3)=\frac{-3-3}{10-4} \cdot ( x-10) $

$\displaystyle \displaystyle (y-3)=\frac{-6}{6} \cdot ( x-10) $

$\displaystyle \displaystyle y-3= 10-x $

$\displaystyle \displaystyle y=7- x $

if you don't trust me :D just put any x from 4 to 10 and you will get exact value of y...

for example x=7 -> y=0 (as you see on graphic)

:D

if u need to represent your function over step functions it would be like this :D

$\displaystyle x(t) = \frac{3t}{4}[u(t)-u(t-4)] + (7-t)[u(t-4) - u(t-10)] $

P.S. you can take any two points from that line and put in formula and you will get same result :D (doesn't have to be "start" and "end")