Suppose G is a group of order 48 and H is a subgroup of order 12, then how many distant right cosets of H are there in G? I thought it was 6. Am I right? If not can u show me which why to go?
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Originally Posted by tigergirl Suppose G is a group of order 48 and H is a subgroup of order 12, then how many distant right cosets of H are there in G? I thought it was 6. Am I right? If not can u show me which why to go? Lagrange's theorem: if $\displaystyle G$ is a finite group and $\displaystyle H\leq G$ then $\displaystyle |G|=[G:H]\cdot |H|$ . Now you can see your mistake. Tonio
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