Find the general solution to the following:

$\displaystyle A(n+1)=2A(n)+3^n-n$

and find the particular solution when A(0)=1.

I have like ten problems this way.

After all my calulations i got $\displaystyle A(k)=c2^k-3^k+k $

is this right? I'm lost on how to find the particular solution. Can anyone help?