My question is
Find all Laurent series expansions of function
f(x)=z^4/(3+z^2) around 1.
Please help!! I will be thankful, if someone can tell me how to do this!!
Thanks!!
The function $\displaystyle \frac{z^{4}}{3+z^{2}}$ is analytic in $\displaystyle z=1$ so that here the Laurent series and the Taylor seriers are the same and is...
$\displaystyle \displaystyle f(z)= \sum_{n=0}^{\infty} f^{(n)} (1)\ \frac{(z-1)^{n}}{n!}$ (1)
Kind regards
$\displaystyle \chi$ $\displaystyle \sigma$