Results 1 to 2 of 2

Thread: Simple complex equality driving me nuts

  1. June 2nd 2010, 11:22 AM #1
    igopogo
    igopogo is offline
    Newbie
    Joined
    May 2010
    Posts
    9

    Simple complex equality driving me nuts

    Find all solutions to sinz = 2i.

    I've gone down the road of sin (z-z^(-1))/2i and its polar counterpart, and also laurent series, but the solutions I get are very complicated. This is a problem from a competency exam so I'm guessing it should have a clever but simple path and answer. Any guidance?
    Last edited by igopogo; June 2nd 2010 at 11:28 AM. Reason: sin z, not sin x!
    Follow Math Help Forum on Facebook and Google+
  2. June 2nd 2010, 12:02 PM #2
    Plato
    Plato is offline
    MHF Contributor
    Joined
    Aug 2006
    Posts
    16,999
    Thanks
    776
    Awards
    1
    MHF Donor
    Quote Originally Posted by igopogo View Post
    Find all solutions to sinz = 2i.
    \sin(z)=\sin(x)\cosh(y)+i\cos(x)\sinh(y)
    So in this solve this system:
    \sin(x)\cosh(y)=0~\&~\cos(x)\sinh(y)=2
    Follow Math Help Forum on Facebook and Google+
« riemann zeta function problem | [SOLVED] Complex analysis, determine the set in the complex plane that satisfies... »

Similar Math Help Forum Discussions

  1. Problem is driving me NUTS
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: October 24th 2009, 07:49 PM
  2. Probability help (this is driving me nuts) #2
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: September 16th 2009, 11:11 AM
  3. questions driving me nuts!!!
    Posted in the Algebra Forum
    Replies: 1
    Last Post: May 13th 2009, 03:20 AM
  4. Driving me nuts!!! please help
    Posted in the Calculus Forum
    Replies: 2
    Last Post: November 7th 2008, 10:16 AM
  5. Driving me nuts !
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: September 17th 2008, 02:33 PM

Search Tags


/mathhelpforum @mathhelpforum