Hi! I want to ask if is is Lebesgue-measurable? If yes why? This is true also for R, R^3 and so on? Are they Peano-Jordan measurable? I thought they were because their complementar is empty. Sorry for my english. Thank you.
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Originally Posted by venturozzaccio Hi! I want to ask if is is Lebesgue-measurable? If yes why? This is true also for R, R^3 and so on? Are they Peano-Jordan measurable? I thought they were because their complementar is empty. Sorry for my english. Thank you. If you have a sigma algebra on any space it will contain the entire space. This holds for any sigma algebra so the whole space is always measurable.
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