Hi! I want to ask if is $\displaystyle R^2$ is Lebesgue-measurable?

If yes why?

This is true also for R, R^3 and so on?

Are they Peano-Jordan measurable?

I thought they were because their complementar is empty. Sorry for my english. Thank you.

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- May 29th 2010, 04:23 AMventurozzacciois R Lebesgue-measurable?
Hi! I want to ask if is $\displaystyle R^2$ is Lebesgue-measurable?

If yes why?

This is true also for R, R^3 and so on?

Are they Peano-Jordan measurable?

I thought they were because their complementar is empty. Sorry for my english. Thank you. - May 30th 2010, 01:46 AMFocus