This might seem easy, but could anyone share the trick how to do the following sums? the sum of 8^n/(3n)!, n goes from 0 to infinity the sum of 27^n/(3n+1)!, n goes from 0 to infinity Any input is appreciated!
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Originally Posted by nngktr This might seem easy, but could anyone share the trick how to do the following sums? the sum of 8^n/(3n)!, n goes from 0 to infinity Let be a complex cube root of 1. Then However, is equal to 3 if n is a multiple of 3, and 0 otherwise. Therefore The expression on the right should obviously be real, so you need to plug in the value for and check that this is indeed the case.
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