Thread: Increasing absolute min

Prove: If I:=[a,b] is an interval and f:I->R, R,reals is an increasing function, then the point a [respectively,b] is an absolute minimum [respectively, maximum] point for f on I. If f is strictly increasing, then a is the only absolute minimum point for f on I.

Originally Posted by apple2010

Prove: If I:=[a,b] is an interval and f:I->R, R,reals is an increasing function, then the point a [respectively,b] is an absolute minimum [respectively, maximum] point for f on I. If f is strictly increasing, then a is the only absolute minimum point for f on I.

This is merely unraveling the definitions. What do you think?