Evaluate .
This function has an isolated singularity at .
I tried this so many times, but still can't get it. Can I get some help please?
When z = 0, the function has a zero of order 2 in the numerator, and also a zero of order 2 in the denominator. Therefore this singularity is removable. There are no other singularities inside the contour, so the integral must be 0.