# Math Help - Complex Analysis - finding roots soliving equation

1. ## Complex Analysis - finding roots soliving equation

Hi, I was hoping if someone could help me figure out how to find the solutions of the equation.

e^iz = i

2. Originally Posted by thorabba
Hi, I was hoping if someone could help me figure out how to find the solutions of the equation.

e^iz = i

$e^{iz}=i = e^{i\left(\frac{\pi}{2}+n\cdot 2\pi\right)}, n\in \mathbb{Z}$
Thus $z = \tfrac{\pi}{2}+n\cdot 2\pi$, $n\in \mathbb{Z}$.