Hi, I was hoping if someone could help me figure out how to find the solutions of the equation. e^iz = i thanks in advance
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Originally Posted by thorabba Hi, I was hoping if someone could help me figure out how to find the solutions of the equation. e^iz = i thanks in advance Let me do it in a sloppy way like this: $\displaystyle e^{iz}=i = e^{i\left(\frac{\pi}{2}+n\cdot 2\pi\right)}, n\in \mathbb{Z}$ Thus $\displaystyle z = \tfrac{\pi}{2}+n\cdot 2\pi$, $\displaystyle n\in \mathbb{Z}$.
ahhh i see, thanks so much i was half way there. i got to z = pi/2. thanks once again!!
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