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Math Help - Complex Analysis - finding roots soliving equation

  1. #1
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    Complex Analysis - finding roots soliving equation

    Hi, I was hoping if someone could help me figure out how to find the solutions of the equation.

    e^iz = i

    thanks in advance
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  2. #2
    Super Member Failure's Avatar
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    Quote Originally Posted by thorabba View Post
    Hi, I was hoping if someone could help me figure out how to find the solutions of the equation.

    e^iz = i

    thanks in advance
    Let me do it in a sloppy way like this:

    e^{iz}=i = e^{i\left(\frac{\pi}{2}+n\cdot 2\pi\right)}, n\in \mathbb{Z}

    Thus z = \tfrac{\pi}{2}+n\cdot 2\pi, n\in \mathbb{Z}.
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  3. #3
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    ahhh i see, thanks so much i was half way there.

    i got to z = pi/2.

    thanks once again!!
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