Thread: Complex Analysis - finding roots soliving equation

1. Complex Analysis - finding roots soliving equation

Hi, I was hoping if someone could help me figure out how to find the solutions of the equation.

e^iz = i

thanks in advance

2. Originally Posted by thorabba
Hi, I was hoping if someone could help me figure out how to find the solutions of the equation.

e^iz = i

thanks in advance
Let me do it in a sloppy way like this:

$e^{iz}=i = e^{i\left(\frac{\pi}{2}+n\cdot 2\pi\right)}, n\in \mathbb{Z}$

Thus $z = \tfrac{\pi}{2}+n\cdot 2\pi$, $n\in \mathbb{Z}$.

3. ahhh i see, thanks so much i was half way there.

i got to z = pi/2.

thanks once again!!