A example of function $\displaystyle f:R\to R$ that no satify Lipschitz condition $\displaystyle \lambda$ in all R, but continuous in all R?
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Originally Posted by rmorin A example of function $\displaystyle f:R\to R$ that no satify Lipschitz condition $\displaystyle \lambda$ in all R, but continuous in all R? $\displaystyle f(x)=x^2$ ... Tonio
Originally Posted by rmorin A example of function $\displaystyle f:R\to R$ that no satify Lipschitz condition $\displaystyle \lambda$ in all R, but continuous in all R? Originally Posted by tonio $\displaystyle f(x)=x^2$ ... Tonio Haha! I bet he meant uniformly continuous, huh?
i think it's probably that thing. but $\displaystyle f(x)=\sqrt x$ on $\displaystyle x\in[0,\infty)$ is a good choice.
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