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Math Help - Reducing the conic?

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    Reducing the conic?

    How does one reduce the conic 4x^2+16x+y^2-6y+21=0 to standard form?
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    Quote Originally Posted by Unenlightened View Post
    How does one reduce the conic 4x^2+16x+y^2-6y+21=0 to standard form?
    Complete the square: 4x^2+ 16x= 4(x^2+ 4x)= 4(x^2+ 4x+ 4- 4)= 4(x+ 2)^2- 16 and y^2- 6y= y^2- 6y+ 9- 9= (y- 3)^2- 9.
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