# Analysis Question

• Apr 18th 2010, 03:22 PM
villa223
Analysis Question
Hello,

Can you help with finding the first 5 terms of a Laurent Series centered at z0 = 0 for (1/e^z-1) using power series divison?

Thank you
• Apr 19th 2010, 03:29 AM
HallsofIvy
Since $e^z= \sum_{n=0}^\infty \frac{z^n}{n!}$, $e^z- 1= \sum_{n=1}^\infty \frac{z^n}{n!}$.

Divide 1 by that power series.