Define f(x)=sqrt(x+sqrt(x+sqrt(x))) for x >=0. Determine where f is differentiable and compute the derivative.
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Originally Posted by tn11631 Define f(x)=sqrt(x+sqrt(x+sqrt(x))) for x >=0. Determine where f is differentiable and compute the derivative. Chain rule! $\displaystyle f'(x) = \frac{1}{2(x+\sqrt{x+\sqrt{x}})^{1/2}}*[1+(\frac{1}{2(x+\sqrt{x})^{1/2}})*(1+\frac{1}{2x^{1/2}})] $ Odds are I screwed up somewhere
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