Prove that as

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- April 15th 2010, 11:40 AMSlazenger3Proving a limit of a function
Prove that as

- April 15th 2010, 11:48 AMchiph588@
- April 15th 2010, 11:58 AMDrexel28
- April 15th 2010, 12:42 PMchiph588@
- April 15th 2010, 04:56 PMLaurent
A common proof (valid for any coefficients) would go along these lines: dividing numerator and denominator by , we have . Under this form, the limits of the terms are immediate to see; in particular, the numerator goes to and the denominator converges to 1, hence the ratio goes to .