Originally Posted by

**Rapha** (B) You already know the euclidean vector of the line - it is (2,2,0) (you calculated (2,2,2) instead...) . This is the vector you should use, because you know it is orthogonal/perpendicular to the plane p

**So the line you need is**

L: OP + t*(2,2,0)

If you substitute t = 0 the line L goes through P.

(C) Of course the distance got to be 0, because the line is not parallel to the plane.

So you can calculate the intersection point of L and P or you can use the 'hesse normal form'.

Whatever you like.

Rapha