Hi,

I would like to show that the sequence $\displaystyle \{1+(-2)^n\}$ diverges. Here is my attempt.

The sequence converges to some element $\displaystyle L \in \mathbb{R}$ iff for all $\displaystyle \epsilon > 0,\,\, \exists N \in \mathbb{N}$ such that $\displaystyle n > N \implies |a_n - L| < \epsilon$. My aim is to show that there is an epsilon for which no positive integer N satisfies this requirement.

Choose $\displaystyle \epsilon = 1$. Then there exists an N such that if n > N then $\displaystyle |1+(-2)^n - L| < 1$.

Now let k be a positive odd integer such that k > N, then

$\displaystyle |1+(-2)^{k+1} - L| < 1$

so $\displaystyle |1+2^{k+1} - L| < 1$

that is $\displaystyle -1 < 1+2^{k+1} - L < 1$

so $\displaystyle -2 < 2^{k+1} - L < 0,\,\,\implies L > 2^{k+1}$

and by a similar argument we can show that if we take k to be some even integer such that k > N then

$\displaystyle L > 2^{k}$

But we can always find an even AND odd k such that the following inequalities are false for any real number L.

However there's something in the back of my mind which I'm not happy with. I don't like how I finished the proof, it doesn't seem quite sound to me. I was wondering if someone could point me in the right direction to finish it off or let me know where I've gone wrong and perhaps suggest a better approach.

Thanks in advance

Stonehambey