Let be the square with vertices 0, 1, , traversed counterclockwise. Evaluate . I parametrized and then deduced the formula: . I come up with -1+ as the answer. Please verify, thank you.
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Originally Posted by Eudaimonia Let be the square with vertices 0, 1, , traversed counterclockwise. Evaluate . I parametrized and then deduced the formula: . I come up with as the answer. Please verify, thank you. I agree with your answer.
Originally Posted by Opalg I agree with your answer. Why wouldn't the answer be zero under Cauchy's theorem?
Please correct me if I'm wrong, but I don't think f(z)=|z|^2 is holomorphic at 0, and thus it does not meet that requirement of Cauchy's integral theorem.
because |z|^2 = zz* is not analytic Originally Posted by davismj Why wouldn't the answer be zero under Cauchy's theorem?
Originally Posted by xxp9 because |z|^2 = zz* is not analytic duh
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