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Math Help - Show that function is a pre-metric

  1. #1
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    Show that function is a pre-metric

    Let # : PxP->R defined as #((x1,y1),(x2,y2))=SquareRoot of : (1/16(x2-x1)^2+1/9(y2-y1)^2.

    Show that # is a premetric but you dont have to check the triangle inequality.
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  2. #2
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    Quote Originally Posted by nikie1o2 View Post
    Let # : PxP->R defined as #((x1,y1),(x2,y2))=SquareRoot of : (1/16(x2-x1)^2+1/9(y2-y1)^2.
    I for one, connot read that. Can you post the question using LaTeX?
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  3. #3
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    ..

    Quote Originally Posted by Plato View Post
    I for one, connot read that. Can you post the question using LaTeX?
    \sqrt{\frac{\1}{16}(x_{2}-x_{1})^2+\frac{\1}{9}(Y_{2}-Y_{1})^2}
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  4. #4
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by nikie1o2 View Post
    Let # : PxP->R defined as #((x1,y1),(x2,y2))=SquareRoot of : (1/16(x2-x1)^2+1/9(y2-y1)^2.

    Show that # is a premetric but you dont have to check the triangle inequality.
    Come on is \#(x,y)\geqslant 0 and \#(x,x)=0??
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  5. #5
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    Quote Originally Posted by nikie1o2 View Post
    \sqrt{\frac{\1}{16}(x_{2}-x_{1})^2+\frac{\1}{9}(Y_{2}-Y_{1})^2}
    I am trying to but i keep getting an error... not to technological savvy
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  6. #6
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by nikie1o2 View Post
    \sqrt{\frac{\1}{16}(x_{2}-x_{1})^2+\frac{\1}{9}(Y_{2}-Y_{1})^2}
    \#\left((x_1,x_2),(y_1,y_2)\right)=\sqrt{\frac{(x_  2-x_1)^2}{16}+\frac{(y_2-y_1)^2}{9}}
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