If a set S contains an unbounded sequence , show that the function defined by for all in , is continuous, but unbounded. and If a set S contains a sequence that converges to a point in S, show that the function defined by for all in , is continuous and unbounded
All I could figure out was that
for the first case, contains an unbounded sequence. We can set, for every index n, and thus every subsequence of this sequence is unbounded and fails to converge.
How can it be proven for the defined function?
Also in the second part, has a sequence that converges to 0 that is not in S.
Again I am not being able to do this for the given function.