Originally Posted by

**tn11631** Yikes! I feel like were all having trouble with uniform continuity...

Use the definition of uniform continuity to show that $\displaystyle \sqrt{x}$ is uniformly continuous on [0,$\displaystyle \infty$) (relative to [0,$\displaystyle \infty$))

For this, do I have to show that $\displaystyle \sqrt{x}$ is uniformly continuous on [0,2] and then show that it is uniformly continuous on [1,$\displaystyle \infty$) before I can show its uniformly continuous on [0,$\displaystyle \infty$)?