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Math Help - show that f is continuous at -3

  1. #1
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    show that f is continuous at -3

    Define f:[-4,0]->R by f(x)=2 x^2-18/x+3 for x \neq-3 and f(-3)= -12. Show that f is continuous at -3.


    At first I was going to try to show that the lim_(x->-3)= -12 and I was going to reduce and stuff but im getting lost because its not working out smoothly. Also, can I just go ahead and show that (with help) or do I have to show a proof of it?
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  2. #2
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    Sorry I kept thinking the denominator was x-3...So in the case, if I show the 2x^2-18/x+3 =(2x-6) and that the lim_(x->-3) 2x-6=-12 is that all i have to do to show that f is continuous at -3? since the lim as x->-3 of f(x)=f(-3)? Or again do I have to show a proof?
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