Let S be contained in and let A be the set of accumulation points of S. Prove S is dense in iff. A=

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- March 18th 2010, 09:36 PMpirouetteAccumulation points, dense set
Let S be contained in and let A be the set of accumulation points of S. Prove S is dense in iff. A=

- March 19th 2010, 07:22 AMFocus
What is your definition of dense? Is it that for each ball in the reals, it contains a point of S?

If so then suppose that S is dense. Let , then for each open set around x, it contains an element of S. Hence . As x was arbitrary, we have that .

Similarly the other way round.