Uniformly Continuous.

**charikaar** · March 12th 2010, 07:41 AM

Prove or disapprove f(x) is uniformly continuous
f(x)=(sinx)/x for x not equal to zero.
and f(x)=1 for x=0

I know f(x) is uniformly continous but I can't prove it. how do i show the derivative $(xcosx-sinx)/x^{2}$ is bounded.

thanks

**1234567** · March 12th 2010, 11:33 AM

Originally Posted by charikaar

Prove or disapprove f(x) is uniformly continuous
f(x)=(sinx)/x for x not equal to zero.
and f(x)=1 for x=0

I know f(x) is uniformly continous but I can't prove it. how do i show the derivative $(xcosx-sinx)/x^{2}$ is bounded.

thanks

Show that the derivative is continous

**chisigma** · March 12th 2010, 11:42 AM

Take into account that the coefficients of McLaurin expansion of $x\cdot \cos x - \sin x$ of degree < 3 are equal to zero, so that is $f^{'}(0)=0$ and that both the functions $\frac{\cos x}{x}$ and $\frac{\sin x}{x^{2}}$ tend to 0 if x tends to infinity...

Kind regards

$\chi$ $\sigma$

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