function

**summerset353** · March 7th 2010, 11:19 AM

g(x)= |_x_|

What do these brackets mean?

**southprkfan1** · March 7th 2010, 11:43 AM

Originally Posted by summerset353

g(x)= |_x_|

What do these brackets mean?

It's the largest integer less than or equal to x

**summerset353** · March 7th 2010, 11:49 AM

would the derivative of |_x_| be equal to 1? Or is it different because of the brackets?

**southprkfan1** · March 7th 2010, 11:56 AM

Originally Posted by summerset353

would the derivative of |_x_| be equal to 1? Or is it different because of the brackets?

Well looking at x on the interval [0,1), g(x) = 0 for all x....

**Drexel28** · March 7th 2010, 07:46 PM

Originally Posted by summerset353

would the derivative of |_x_| be equal to 1? Or is it different because of the brackets?

Is the function even continuous? If you look at the function $f<img src=$ n,n+1)\mapsto\mathbb{R},\text{ }n\in\mathbb{N}" alt="f

n,n+1)\mapsto\mathbb{R},\text{ }n\in\mathbb{N}" /> with $f(x)=\left \lfloor x\right\rfloor$ then in fact $f(x)=1$ . And so $f'(x)=0$ .

Thread: function