# function

• Mar 7th 2010, 11:19 AM
summerset353
function
g(x)= |_x_|

What do these brackets mean?
• Mar 7th 2010, 11:43 AM
southprkfan1
Quote:

Originally Posted by summerset353
g(x)= |_x_|

What do these brackets mean?

It's the largest integer less than or equal to x
• Mar 7th 2010, 11:49 AM
summerset353
would the derivative of |_x_| be equal to 1? Or is it different because of the brackets?
• Mar 7th 2010, 11:56 AM
southprkfan1
Quote:

Originally Posted by summerset353
would the derivative of |_x_| be equal to 1? Or is it different because of the brackets?

Well looking at x on the interval [0,1), g(x) = 0 for all x....
• Mar 7th 2010, 07:46 PM
Drexel28
Quote:

Originally Posted by summerset353
would the derivative of |_x_| be equal to 1? Or is it different because of the brackets?

Is the function even continuous? If you look at the function $\displaystyle f:(n,n+1)\mapsto\mathbb{R},\text{ }n\in\mathbb{N}$ with $\displaystyle f(x)=\left \lfloor x\right\rfloor$ then in fact $\displaystyle f(x)=1$. And so $\displaystyle f'(x)=0$.